Q. $\int_{}^{}{e^{x}\left( \frac{2}{x} - \frac{2}{x^{2}} \right)}dx$ is equal to
A) $\frac{e^{x}}{x} + c$
B) $\frac{e^{x}}{2x^{2}} + c$
C) $\frac{2e^{x}}{x} + c$
D) $\frac{2e^{x}}{x^{2}} + c$
Explanation
(c)
$\int_{}^{}{e^{x}\left( \frac{2}{x} - \frac{2}{x^{2}} \right)}dx$
$= \frac{2e^{x}}{x} + c\ \lbrack\because f(x) = \frac{2}{x}\ and\ f^{'}(x) = - \frac{2}{x^{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.