(d)
Since, $\int_{2}^{4}{\{ 3 - f(x)}\} dx = 7$
$\Rightarrow \ 3\lbrack x\rbrack_{2}^{4} - \int_{2}^{4}{f(x)}dx = 7$
$\Rightarrow \ \int_{2}^{4}{f(x)}dx = 6 - 7 = - 1$
$\therefore\ \int_{- 1}^{2}{f(x)}dx = \int_{- 1}^{4}{f(x)}dx - \int_{2}^{4}{f(x)}dx$
$= 4 - ( - 1) = 5$