Q. $\int_{}^{}{\frac{mx^{m + 2n - 1} - nx^{n - 1}}{x^{2m + 2n} + 2x^{m + n} + 1}\ dx}$ is equal to

A) $\frac{x^{m}}{x^{m + n} + 1} + c$
B) $\frac{x^{n}}{x^{m + n} + 1} + c$
C) $\frac{x^{m + n} - 1}{x^{m + n} + 1} + c$
D) $- \frac{x^{n}}{x^{m + n} + 1} + c$
Explanation

(d)
Let $I = \int_{}^{}{\frac{mx^{m + 2n - 1} - nx^{n - 1}}{x^{2m + 2n} + 2x^{m + n} + 1}\ dx}$
$= \int_{}^{}{\frac{mx^{m + 2n - 1} - nx^{n - 1}}{\left( 1 + x^{m + n} \right)^{2}}dx}$
$\therefore I = \int_{}^{}{\frac{mx^{m - 1} - \frac{n}{x^{n + 1}}}{\left( \ x^{m} + \frac{1}{x^{n}}\ \right)^{2}}dx}$
Let $x^{m} + \frac{1}{x^{n}} = t$
$\Rightarrow mx^{m - 1} - \frac{n}{x^{n + 1}}dx = dt$
$\therefore I = \int_{}^{}{\frac{1}{t^{2}}dt = - \frac{1}{t} + c}$
$= \frac{- 1}{\left( \ x^{m} + \frac{1}{x^{n}}\ \right)} + c = \frac{- x^{n}}{x^{m + n} + 1} + c$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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