Q. If $d\left\lbrack f(x) \right\rbrack = e^{\tan x}\sec^{2}{x\ dx,\ then\ f(x)}$ is equal to
A) $e^{\tan x} + c$
B) $e^{\sec^{2}x} + c$
C) $e^{\sin x} + c$
D) None of these
Explanation
(a)
We have, $d\left\lbrack f(x) \right\rbrack = e^{\tan x}\sec^{2}{x\ dx}$
On integrating $w.r.t$ $x$, we get
$f(x) = e^{\tan x} + c$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.