Q. The value of $\int_{0}^{\frac{\pi}{2}}\frac{{(\sin{x + \cos{x)}}}^{2}}{\sqrt{1 + \sin{2x}}}\ dx$ is

A) 0
B) 1
C) 2
D) 3
Explanation

(c)
Let $I = \int_{0}^{\frac{\pi}{2}}\frac{{(\sin{x + \cos{x)}}}^{2}}{\sqrt{\sin^{2}x + \cos^{2}x + 2\sin x\cos x}}\ dx$
$= \int_{0}^{\frac{\pi}{2}}\frac{{(\sin{x + \cos{x)}}}^{2}}{\sqrt{\left( \sin x + \cos x \right)^{2}}}\ dx$
$= \int_{0}^{\frac{\pi}{2}}{(\sin x + \cos x)}\ dx$
$= \left\lbrack - \cos x + \sin x \right\rbrack_{0}^{\frac{\pi}{2}} = - 0 + 1 + 1 - 0 = 2$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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