Q. The value of $\int_{}^{}\frac{e^{5\log_{e}x} - e^{4\log_{e}x}}{e^{3\log_{e}x} - e^{2\log_{e}x}}\ dx$ is

A) $x^{2} + c$
B) $\frac{x^{2}}{2} + c$
C) $\frac{x^{3}}{3} + c$
D) $\frac{x}{2} + c$
Explanation

(c)
$\int_{}^{}\frac{e^{5\log_{e}x} - e^{4\log_{e}x}}{e^{3\log_{e}x} - e^{2\log_{e}x}}\ dx = \int_{}^{}\frac{e^{\log_{e}x^{5}} - e^{\log_{e}x^{4}}}{e^{\log_{e}x^{3}} - e^{\log_{e}x^{2}}}\ dx$
$= \int_{}^{}{\frac{x^{5} - x^{4}}{x^{3} - x^{2}}dx = \int_{}^{}\frac{x^{4}(x - 1)}{x^{2}(x - 1)}}\ dx$
$= \int_{}^{}x^{2}\ dx = \frac{x^{3}}{3} + c$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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