Q. $\int_{- 2}^{2}{\left( x - |x| \right)dx}$ is equal to

A) 0
B) 2
C) 4
D) $- 4$
Explanation

(d)
We know that, $|x| = \left\{ \begin{matrix}
- x,\ \ \ if\ \ \ x < 0\ \\
x,\ \ \ \ if\ \ \ \ \ x \geq 0
\end{matrix} \right.\$
$\therefore\int_{- 2}^{2}{\left( x - |x| \right)dx = \int_{- 2}^{0}{\left\{ \ \right.\ x - ( - x)\} dx + \int_{0}^{2}{(x - x)dx}}}$
$= \int_{- 2}^{0}{2x\ dx + 0}$
$= 2\left\lbrack \frac{x^{2}}{2} \right\rbrack_{- 2}^{0}$
$= 2\left\lbrack 0 - \frac{( - 2)^{2}}{2} \right\rbrack = - 4$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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