Q. $\int_{0}^{2}\frac{2x - 2}{2x - x^{2}}\ dx$ is equal to
A) 0
B) 2
C) 3
D) 4
Explanation
(a)
Let $I = \int_{0}^{2}\frac{2x - 2}{2x - x^{2}}dx$
Put $2x - x^{2} = t\ \Rightarrow \ (2 - 2x)dx = dt$
$I = - \int_{0}^{0}{\frac{dt}{t} = 0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.