(c)
Let $f(x) = e^{{\cos^{2}x}.}\cos^{3}{(2n + 1)x}$
Then, $f(\pi - x) = e^{\cos^{2}{(\pi - x).\ }}\cos^{3}{\lbrack(2n + 1)\pi - (2n + 1)x\rbrack}$
$= - e^{\cos^{2}x}.\cos^{3}{(2n + 1)x}$
$\Rightarrow f(\pi - x) = - f(x)$
$\therefore f(x)\ is\ an\ odd\ function.$
Hence, $\int_{0}^{\pi}e^{{\cos^{2}\ x}\ }.\cos^{3}{(2n + 1)x\ dx = 0}$