Q. Value of the integral $\int_{–\pi/2}^{\pi/2}{\cos{x\ dx}}is$

A) 4
B) 2
C) 0
D) 1
Explanation

(b)
Let $I = \int_{- \pi/2}^{\pi/2}{\cos{x\ dx}}$
Since, $\cos( - x) = \cos x$
$\therefore I = 2\int_{0}^{\pi/2}{\cos{x\ dx = 2\left\lbrack \sin x \right\rbrack_{0}^{\pi/2}} = 2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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