(b) Let $I = \int_{- \pi/2}^{\pi/2}{\cos{x\ dx}}$ Since, $\cos( - x) = \cos x$ $\therefore I = 2\int_{0}^{\pi/2}{\cos{x\ dx = 2\left\lbrack \sin x \right\rbrack_{0}^{\pi/2}} = 2}$
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