Q. $\int_{}^{}\frac{x^{4} + x^{2} + 1}{x^{2} - x + 1\ }\ dx$ is equal to
A) $\frac{x^{3}}{3} - \frac{x^{2}}{2} + x + c$
B) $\frac{x^{3}}{3} + \frac{x^{2}}{2} + x + c$
C) $\frac{x^{3}}{3} - \frac{x^{2}}{2} - x + c$
D) $\frac{x^{3}}{3} + \frac{x^{2}}{2} - x + c$
Explanation
(b)
$\int_{}^{}\frac{x^{4} + x^{2} + 1}{x^{2} - x + 1\ }\ dx = \int_{}^{}{(x^{2} + x + 1)}\ dx$
$= \frac{x^{3}}{3} + \frac{x^{2}}{2} + x + c$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.