Q. $\int_{0}^{2}{\left\lbrack x^{2} \right\rbrack dx}$is

A) $2 - \sqrt{2}$
B) $2 + \sqrt{2}$
C) $\sqrt{2} - 1$
D) $- \sqrt{2} - \sqrt{3} + 5$
Explanation

(d)
$\int_{0}^{2}{\left\lbrack x^{2} \right\rbrack dx}$
$= \int_{0}^{1}{\left\lbrack x^{2} \right\rbrack dx + \int_{1}^{\sqrt{2}}{\left\lbrack x^{2} \right\rbrack dx = \int_{\sqrt{2}}^{\sqrt{3}}{\left\lbrack x^{2} \right\rbrack dx + \int_{\sqrt{3}}^{2}{\left\lbrack x^{2} \right\rbrack dx}}}}$
$= \int_{0}^{1}{0\ dx + \int_{1}^{\sqrt{2}}{1dx + \int_{\sqrt{2}}^{\sqrt{3}}{2\ dx + \int_{\sqrt{3}}^{2}{3dx}}}}$
$= \lbrack x\rbrack_{1}^{\sqrt{2}} + \lbrack 2x\rbrack_{\sqrt{2}}^{\sqrt{3}} + \lbrack 3{x\rbrack}_{\sqrt{3}}^{2}$
$= 5 - \sqrt{3} - \sqrt{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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