Q. The value of $\int_{2}^{3}{\frac{x + 1}{x^{2}(x - 1)}\ dx}$ is

A) $\log{\frac{16}{9} + \frac{1}{6}}$
B) $\log{\frac{16}{9} - \frac{1}{6}}$
C) $2\log{2 - \frac{1}{6}}$
D) $\log{\frac{4}{3} - \frac{1}{6}}$
Explanation

(b)
Let $I = \int_{2}^{3}{\frac{x + 1}{x^{2}(x - 1)}dx}$
$= \int_{2}^{3}{\left( \frac{- 2}{x} - \frac{1}{x^{2}} + \frac{2}{x - 1} \right)dx}$
$= \left\lbrack - 2\log{x +}\frac{1}{x} + 2\log(x - 1) \right\rbrack_{2}^{3}$
$= \left\lbrack 2\log{\left( \frac{x - 1}{x} \right) + \frac{1}{x}} \right\rbrack_{2}^{3} = \left\lbrack 2\left( \log{\frac{2}{3} - \log\frac{1}{2}} \right) + \frac{1}{3} - \frac{1}{2} \right\rbrack$
$= 2\log{\frac{4}{3} - \frac{1}{6} = \log{\frac{16}{9} - \frac{1}{6}}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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