Q. $\int_{}^{}{\frac{x^{2} + x - 6}{(x - 2)(x - 1)}dx}$
A) $x + 2\log{(x - 1) + c}$
B) $2x + 2\log{(x - 1) + c}$
C) $x + 4\log{(1 - x) + c}$
D) $x + 4\log{(x - 1) + c}$
Explanation
(d)
$\int_{}^{}{\frac{x^{2} + x - 6}{(x - 2)(x - 1)}dx = \int_{}^{}\frac{x + 3}{x - 1}}dx$
$= \int_{}^{}1dx + \int_{}^{}\frac{4}{(x - 1)}dx$
$= x + 4\log{(x - 1) + c}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.