Q. $\int_{}^{}{e^{\tan^{- 1}x}\left| \frac{1 + x + x^{2}}{1 + x^{2}} \right|dx}$ is equal to
A) $xe^{\tan^{- 1}x} + c$
B) $x^{2}e^{\tan^{- 1}x\ } + c$
C) $\frac{1}{x}e^{\tan^{- 1}x} + c$
D) None of these
Explanation
The correct answer is Option A: $xe^{\tan^{- 1}x} + c$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.