$f(x) = \min{\left\{ x + 2,\ 1,\ 2 - x \right\},}$ then $\int_{- 2}^{2}{f(x)dx}$ is equal to

Question

Dr. Abubacker · Accepted Answer

(c)
$\int_{- 2}^{2}{f(x)dx} = \int_{- 2}^{- 1}{(x + 2)dx} + \int_{- 1}^{1}{dx} + \int_{1}^{2}{(2 - x)dx}$
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$= \frac{1}{2} + 2 + \frac{1}{2} = 3$

Q. $f(x) = \min{\left\{ x + 2,\ 1,\ 2 - x \right\},}$ then $\int_{- 2}^{2}{f(x)dx}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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