(a) Now, $\int_{}^{}{uv''}\ dx = uv^{'} - \int_{}^{}{u'v'}\ dx$ $= uv^{'} - \left\lbrack vu^{'} - \int_{}^{}{vu''}\ dx \right\rbrack = uv^{'} - vu^{'} + \int_{}^{}{u^{''}v}\ dx$ $\therefore\ a = \int_{}^{}{u''}v\ dx$
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