Q. If $f^{'}(x) = x + \frac{1}{x}$, then the value of $f(x)$ is
A) $x^{2} + \log{x + c}$
B) $\frac{x^{2}}{2} + \log{x + c}$
C) $\frac{x}{2} + \log{x + c}$
D) None of these
Explanation
(b)
Given, $f^{'}(x) = x + \frac{1}{x}$
On integrating both sides, we get
$f(x) = \frac{x^{2}}{2} + \log x + c$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.