Q. $\int_{}^{}{e^{x}\frac{(x - 1)}{x^{2}}\ dx}$ is equal to
A) $\frac{e^{x}}{x^{2}} + c$
B) $\frac{{- e}^{x}}{x^{2}} + c$
C) $\frac{e^{x}}{x} + c$
D) $\frac{{- e}^{x}}{x} + c$
Explanation
(c)
$\int_{}^{}{e^{x}\frac{(x - 1)}{x^{2}}\ dx}$
$= \int_{}^{}{e^{x}\left( \frac{1}{x} - \frac{1}{x^{2}} \right)\ dx}$
$= \frac{e^{x}}{x} + c$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.