Q. $\int_{- \pi}^{\pi}{\frac{\sin^{4}x}{\sin^{4}{x + \cos^{4}x}}dx}$ is equal to

A) $\frac{\pi}{4}$
B) $\frac{\pi}{2}$
C) $\frac{3\pi}{2}$
D) $\pi$
Explanation

(d)
Let $I = 2\int_{0}^{\pi}\frac{\sin^{4}x}{\sin^{4}{x + \cos^{4}{x\ dx}}}$
$= 4\int_{0}^{\pi/2}\frac{\sin^{4}x}{\sin^{4}{x + \cos^{4}x}}$ …(i)
$\Rightarrow I = 4\int_{0}^{\pi/2}\frac{\cos^{4}x}{\sin^{4}{+ \cos^{4}x}}dx$ …(ii)
On adding Eqs. (i) and (ii), we get
$2I = 4\int_{0}^{\pi/2}{1.dx = 2\pi}$
$\Rightarrow \ I = \pi$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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