$\int_{0}^{\pi/2}{\frac{\cos heta}{\sqrt{4 - \sin^{2} heta}}\ d heta}$ is equal to

Question

$\int_{0}^{\pi/2}{\frac{\cos	heta}{\sqrt{4 - \sin^{2}	heta}}\ d	heta}$ is equal to

Dr. Abubacker · Accepted Answer

(b)
$\int_{0}^{\pi/2}{\frac{\cos	heta}{\sqrt{4 - \sin^{2}	heta}}d	heta = \left\lbrack \sin^{- 1}\left( \frac{\sin	heta}{2} ight) ightbrack_{0}^{\pi/2}}$
$= \sin^{- 1}{\left( \frac{1}{2} ight) = \frac{\pi}{6}}$

Q. $\int_{0}^{\pi/2}{\frac{\cos\theta}{\sqrt{4 - \sin^{2}\theta}}\ d\theta}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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