If $\int_{\lbrack x\rbrack}^{\lbrack x\rbrack + 1}{f(t)dt = \lbrack x\rbrack,}$ then the value of $\int_{- 2}^{4}{f(x)dx}$ is equal to

Question

Dr. Abubacker · Accepted Answer

(d)
$\int_{\lbrack xbrack}^{\lbrack xbrack + 1}{f(t)dt = \lbrack xbrack}$
$\int_{- 2}^{- 2 + 1}{f(x)dx = - 2,\ \int_{- 1}^{0}{f(x)dx = - 1,\ldots.\int_{3}^{4}{f(x)dx = 3}}}$
$	herefore\ \ \int_{- 2}^{4}{f(x)dx = - 2} - 1 + 1 + 2 + 3 = 3$

Q. If $\int_{\lbrack x\rbrack}^{\lbrack x\rbrack + 1}{f(t)dt = \lbrack x\rbrack,}$ then the value of $\int_{- 2}^{4}{f(x)dx}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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