Q. $\int_{}^{}{\log{2x}}dx$ is equal to
A) $x\log{2x -}\frac{x^{2}}{2} + c$
B) $x\log{2x -}\frac{x}{2} + c$
C) $x^{2}\log{2x -}\frac{x}{2} + c$
D) $x\log{2x} - x + c\$
Explanation
(d)
Let $I = \int_{}^{}1.\log{2x}dx$
$\Rightarrow \ I = x\log{2x} - \int_{}^{}\frac{1}{2x}.2.x\ dx$
$\Rightarrow \ I = x\log{2x} - x + c$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.