The area enclosed between the curve $y = 1 + x^{2}$, the $x$-axis and the line $y = 5$ is given by

Question

Dr. Abubacker · Accepted Answer

(d)
$Required\ area = \int_{1}^{5}{\ x\ dy = \int_{1}^{5}\sqrt{y - 1}dx}$
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$= \left\lbrack \frac{(y - 1)^{3/2}}{3/2} \right\rbrack_{1}^{5} = \frac{2}{3}\lbrack(4)^{\frac{3}{2}} - 0\rbrack$
$= \frac{16}{3}\ sq\ units$

Q. The area enclosed between the curve $y = 1 + x^{2}$, the $x$-axis and the line $y = 5$ is given by

Explanation

Reviewed by Dr. Abubacker

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