Q. Area bounded by the curve $y = (x - 1)(x - 2)(x - 3)$ and $x$-axis lying between the ordinates $x = 0$ and $x = 3$ is equal to
A) $\frac{9}{4}$ sq unit
B) $\frac{11}{4}$ sq unit
C) $\frac{13}{4}$ sq unit
D) $\frac{15}{4}$ sq unit
Explanation
(b)
Required area
$= \left| \int_{0}^{1}{(x - 1)(x - 2)(x - 3)dx} \right| + \int_{1}^{2}{(x - 1)(x - 2)(x - 3)dx}$
$+ \left| \int_{2}^{3}{(x - 1)(x - 2)(x - 3)dx} \right|$
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$= \frac{9}{4} + \frac{1}{4} + \frac{1}{4} = \frac{11}{4}\ sq\ unit$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.