Q. The area enclosed between the curves $y^{2} = x$ and $y = |x|$ is
A) $\frac{2}{3}\ sq\ unit\$
B) $1\ sq\ unit\$
C) $\frac{1}{6}sq\ unit\$
D) $\frac{1}{3}\ sq\ unit$
Explanation
(c)
$Required\ area = \int_{0}^{1}{\left( \sqrt{x} - x \right)dx}$
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$= \left\lbrack \frac{2}{3}x^{3/2} - \frac{x^{2}}{2} \right\rbrack_{0}^{1} = \frac{1}{6}sq\ unit$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.