The volume of the solid formed by rotating the area enclosed between the curve $y = x^{2}$ and the line $y = 1$ about $y = 1$ is (in cubic unit)

Question

Dr. Abubacker · Accepted Answer

(b)
$Required\ volume = \pi\int_{- 1}^{1}{y^{2}dx = 2\pi\int_{0}^{1}{x^{4}dx}}$
$= 2\pi\left\lbrack \frac{x^{5}}{5} \right\rbrack_{0}^{1} = \frac{2\pi}{5}\ cu\ unit$
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Q. The volume of the solid formed by rotating the area enclosed between the curve $y = x^{2}$ and the line $y = 1$ about $y = 1$ is (in cubic unit)

Explanation

Reviewed by Dr. Abubacker

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