The area bounded by the curves $y = 3x$ and $y = x^{2}$ is (in square unit)

Question

Dr. Abubacker · Accepted Answer

(c)
The intersection points of given curves are (0,0) and (3,9)
$	herefore\ \ Required\ area = \int_{0}^{3}{\left( 3x - x^{2} ight)dx}$
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$= \left\lbrack \frac{{3x}^{2}}{2} - \frac{x^{3}}{3} ightbrack_{0}^{3} = \frac{27}{6} = 4.5\ sq\ units$

Q. The area bounded by the curves $y = 3x$ and $y = x^{2}$ is (in square unit)

Explanation

Reviewed by Dr. Abubacker

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