Q. The area bounded by the curve $x = 3y^{2} - 9$ and the line $x = 0,\ y = 0$ and $y = 1$ is
A) 8 sq unit
B) 8/3 sq unit
C) 3/8 sq unit
D) 3 sq unit
Explanation
(b)
Required area $= \left| \int_{0}^{1}{\left( 3y^{2} - 9 \right)dy} \right|$
$= \left| \left\lbrack y^{3} - 9y \right\rbrack_{0}^{1} \right|$
$= |1 - 9| = 8$ sq unit
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.