Q. The area bounded by the parabola $y^{2} = 8x$ and its latusretum in square unit is
A) 16/3 sq units
B) 32/3 sq units
C) 8/3 sq units
D) 64/3 sq units
Explanation
(b)
$Required\ area = 2\int_{0}^{2}\sqrt{8x}\ dx = 4\sqrt{2}\left\lbrack \frac{x^{3/2}}{3/2} \right\rbrack_{0}^{2}$
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$= 4\sqrt{2}\left\lbrack \frac{2\sqrt{2}}{3/2} \right\rbrack$
$= \frac{32}{3}sq\ units$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.