(d) Required area $= \int_{0}^{1}{\left( \sqrt{x} - x^{2} \right)dx}$ [image:8_image57.jpeg] $= \left\lbrack \frac{2x^{3/2}}{3} - \frac{x^{3}}{3} \right\rbrack_{0}^{1} = \left( \frac{2}{3} - \frac{1}{3} \right) = \frac{1}{3}\ sq\ unit$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.