Q. The area enclosed by $y = 3x - 5,\ y = 0,x = 3\ and\ x = 5\ is\$
A) 12 sq units
B) 13 sq unit
C) $13\frac{1}{2}sq\ unit$
D) 14 sq unit
Explanation
(d)
$Requred\ area = \int_{3}^{5}{(3x - 5)dx}$
$= \left( \frac{{3x}^{2}}{2} - 5x \right)_{3}^{5} = \left( \frac{75}{2} - 25 \right) - \left( \frac{27}{2} - 15 \right)$
$= \frac{75}{2} - 25 - \frac{27}{2} + 15 = \frac{48}{2} - 10 = 14\ sq\ units$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.