(a) Required area $= \int_{1}^{2}{\left( x^{3} - x^{2} \right)dx}$ $= \left( \frac{x^{4}}{4} - \frac{x^{3}}{3} \right)_{1}^{2}$ $= \left( 4 - \frac{8}{3} \right) - \left( \frac{1}{4} - \frac{1}{3} \right) = \frac{17}{22}$
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