(b)
The equation of tangent at (2,3) to the given parabola is
$x = 2y - 4$
[image:8_image67.jpeg]
$\therefore$ Required area
$= \int_{0}^{3}{\{\left( y - 2)^{2} + 1 - 2y + 4 \right\} dy}$
$= \left\lbrack \frac{(y - 2)^{3}}{3} - y^{2} + 5y \right\rbrack_{0}^{3}$
$= \frac{1}{3} - 9 + 15 + \frac{8}{3}$
$= 9\ sq\ units$