Q. The area of the region bounded by the curve ${9x}^{2} + 4y^{2} - 36 = 0$ is
A) $9\ \pi\ sq\ units$
B) $4\ \pi\ sq\ units$
C) $36\pi\ sq\ units$
D) $6\ \pi\ sq\ unit$
Explanation
(d)
$The\ given\ eqution\ of\ curve\ can\ be\ written\ as\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1$
$Here,\ a = 2,\ b = 3$
$\therefore$ Required area$= \pi\ ab$
$= \pi \times 2 \times 3$
$= 6\pi\ sq\ units$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.