Q. Area bounded by $y^{2} = x,\ y = 0,\ x = 1,\ x = 4$ is
A) $\frac{28}{3}\ sq\ units$
B) $\frac{3}{28}\ sq\ units$
C) $\frac{8}{3}\ sq\ units$
D) $\frac{4}{3}\ sq\ units$
Explanation
(a)
$Required\ area = 2\int_{1}^{4}{\sqrt{x}\ dx}$
$= 2\left\lbrack \frac{2}{3}x^{3/2} \right\rbrack_{1}^{4} = \frac{4}{3}\lbrack 8 - 1\rbrack = \frac{28}{3}\ sq\ units$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.