The area bounded by $y = \left| \sin x \right|$, $x$-axis and the lines $|x| = \pi$ is

Question

Dr. Abubacker · Accepted Answer

(c)
$Required\ area = 2\int_{0}^{\pi}{\sin{x\ dx}}$
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$= 2{\lbrack - \cos{x\rbrack}}_{0}^{\pi} = 2\lbrack 1 + 1\rbrack = 4\ sq\ units$

Q. The area bounded by $y = \left| \sin x \right|$, $x$-axis and the lines $|x| = \pi$ is

Explanation

Reviewed by Dr. Abubacker

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