Q. The area common to the circle $x^{2} + y^{2} = 64$ and the parabola $y^{2} = 4x$ is
A) $\frac{16}{3}(4\pi + \sqrt{3})$ sq unit
B) $\frac{16}{3}(8\pi - \sqrt{3})$ sq unit
C) $\frac{16}{3}(4\pi - \sqrt{3})$ sq unit
D) None of these
Explanation
The correct answer is Option B: $\frac{16}{3}(8\pi - \sqrt{3})$ sq unit.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.