Q. The area (in square unit) of the region enclosed by the curves $y = x^{2}$ and $y = x^{3}$ is

A) $\frac{1}{12}$
B) $\frac{1}{6}$
C) $\frac{1}{3}$
D) $1$
Explanation

(a)
Intersection point of given curves is (1,1)
[image:8_image101.jpeg]
$\therefore Area = \int_{0}^{1}{\left( x^{2} - x^{3} \right)dx}$
$= \left\lbrack \frac{x^{3}}{3} - \frac{x^{4}}{4} \right\rbrack_{0}^{1}$
$= \frac{1}{12}\ sq\ unit$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.