Q. The solution of the differential equation $\left\{ \frac{1}{x} - \frac{y^{2}}{(x - y)^{2}} \right\} dx + \left\{ \frac{x^{2}}{(x - y)^{2}} - \frac{1}{y} \right\} dy = 0$ is

A) In $\left| \frac{x}{y}\ \right| + \frac{xy}{(x - y)} = c$
B) In $|\ xy\ | + \frac{xy}{(x - y)} = c$
C) $\frac{xy}{(x - y)} = ce^{x/y}$
D) $\frac{xy}{(x - y)} = ce^{xy}$ (where $c$ is arbitrary constant)
Explanation

(a)
The given equation can be written as
$\left( \frac{dx}{x} - \frac{dy}{y} \right) + \frac{(x^{2}dy - y^{2}dx)}{(x - y)^{2}} = 0$
$\Rightarrow \ \left( \frac{dx}{x} - \frac{dy}{y} \right) + \frac{\left( \frac{dy}{y^{2}} - \frac{dx}{x^{2}} \right)}{\left( \frac{1}{y} - \frac{1}{x} \right)^{2}} = 0$
$\Rightarrow \ \left( \frac{dx}{x} - \frac{dy}{y} \right) + \frac{\frac{dy}{y^{2}} - \frac{dx}{x^{2}}}{\left( \frac{1}{x} - \frac{1}{y} \right)^{2}} = 0$
On integrating both sides, we get
In $|x| - In\ |y| - \frac{1}{\left( \frac{1}{x} - \frac{1}{y} \right)} = c$
$\Rightarrow$ In $\left| \frac{x}{y} \right| - \frac{xy}{(y - x)} = c$
$\Rightarrow$ In $\left| \frac{x}{y} \right| + \frac{xy}{(x - y)} = c$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.