Q. The order and degree of the differential equation $y = \frac{dy}{dx} + \sqrt{a^{2}\left( \frac{dy}{dx} \right)^{2} + b^{2}}$ is

A) $3,1$
B) $1,2$
C) $2,1$
D) $1,3$
Explanation

(b)
Given differential equation can be rewritten as
$y - x\ \frac{dy}{dx} = \sqrt{a^{2}\ \left( \frac{dy}{dx} \right)^{2} + b^{2}}$
$\Rightarrow$ $y^{2} + \left( x\ \frac{dy}{dx} \right)^{2} - 2yx\ \frac{dy}{dx} = a^{2}\left( \frac{dy}{dx} \right)^{2} + b^{2}$
Here, order is 1 and degree is 2.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.