Q. The solution of $\frac{dy}{dx} = \cos{(x + y) + \sin{(x + y)}}$ is
A) $\log{\left\lbrack 1 + \tan\left( \ \frac{x + y}{2}\ \right) \right\rbrack + c = 0}$
B) $\log{\left\lbrack 1 + \tan\left( \ \frac{x + y}{2}\ \right) \right\rbrack = x + c}$
C) $\log{\left\lbrack 1 - \tan\left( \ \frac{x + y}{2}\ \right) \right\rbrack = x + c}$
D) None of these
Explanation
The correct answer is Option B: $\log{\left\lbrack 1 + \tan\left( \ \frac{x + y}{2}\ \right) \right\rbrack = x + c}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.