Q. For solving $\frac{dy}{dx} = 4x + y + 1$, suitable substitution is
A) $y = vx$
B) $y = 4x + v$
C) $y = 4x$
D) $y + 4x + 1 = v$
Explanation
(d)
$y + 4x + 1 = V$ is the suitable substitution
$\because\ \frac{dy}{dx} = f(ax + by + c)$ is
Solvable for substituting
$ax + by + c = V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.