(c)
$y^{2} = 2c(x + c^{\frac{2}{3}})$
$\Rightarrow$ $2y\ \frac{dy}{dx} = 2c \Rightarrow c = y\ \frac{dy}{dx}$
$\therefore$ $y^{2} = 2y\ \frac{dy}{dx}\left( x + \left( y\ \frac{dy}{dx} \right)^{\frac{2}{3}} \right)$
$\Rightarrow$ $\left( \frac{y}{2\frac{dy}{dx}} - x \right) = \left( y\ \frac{dy}{dx} \right)^{\frac{2}{3}}$
$\Rightarrow$ $\left( y - 2x\ \frac{dy}{dx} \right)^{3} = \left( 2\ \frac{dy}{dx} \right)^{3}\left( y\ \frac{dy}{dx} \right)^{2}$
$\Rightarrow$ $\left( y - 2x\ \frac{dy}{dx} \right)^{3} = 8y^{2}\left( \frac{dy}{dx} \right)^{5}$
Here, order=1, degree=5