Q. If $c_{1},c_{2},c_{3},c_{4},c_{5}\ and\ \ c_{6}$ are constants, then the order of the differential equation whose general solution is given by $y = c_{1}\cos{(x + c_{2}}) + c_{3}\sin{(x + c_{4}}) + c_{5}e^{x} + c_{6}$ is

A) $6$
B) $5$
C) $4$
D) $3$
Explanation

(c)
Given, $y = c_{1}\cos{(x + c_{2})} + c_{3}\sin{(x + c_{4})} + c_{5}e^{x} + c_{6}$
$y = c_{1}\left\lbrack \cos x\cos c_{2} - \sin x\sin c_{2} \right\rbrack$
$+ c_{3}\lbrack\sin{x\cos{c_{4} + \cos{x\sin c_{4}}}\ }\rbrack + c_{5}e^{x} + c_{6}$
$= \cos x\left( c_{1}\cos c_{2} + c_{3}\sin c_{4} \right) + \sin x\left( - c_{1}\sin c_{2} + c_{3}\cos c_{4} \right) + c_{5}e^{x} + c_{6}$
$= A\cos x + B\sin x + Ce^{x} + D$
Where $A = c_{1}\cos c_{2} + c_{3}\sin c_{4}$
$B = - c_{1}\sin c_{2} + c_{3}\cos c_{4},\ \ C = c_{5},\ D = c_{6}$
Hence, order is 4.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.