Q. If the integrating factor of the differential equation $\frac{dy}{dx} + P(x)y = Q(x)$ is $x$, then $P(x)$ is

A) $x$
B) $\frac{x^{2}}{2}$
C) $\frac{1}{x}$
D) $\frac{1}{x^{2}}$
Explanation

(c)
Given, $IF = x$
$\therefore$ $e^{\int_{}^{}{P\ dx}} = x$
$\Rightarrow$ $\int_{}^{}Pdx = \log x$
$\Rightarrow$ $P = \frac{d}{dx}\log x = \frac{1}{x}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.