Q. Integral curve satisfying $y^{'} = \frac{x^{2} + y^{2}}{x^{2} - y^{2}},\ y(1) = 2$ has the slope at the point (1, 0) of the curve is equal to

A) $- 5/3$
B) $- 1$
C) 1
D) $5/3$
Explanation

(c)
$\frac{dy}{dx} = \frac{x^{2} + y^{2}}{x^{2} - y^{2}}$, where, $\frac{dy}{dx}$ is the slope of the curve.
$\therefore\left( \ \frac{dy}{dx}\ \right)_{(1,0)} = \frac{1 + 0}{1 - 0} = 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.