The degree of the differential equations $x = 1 + \left( \frac{dy}{dx} \right) + \frac{1}{2!}\left( \frac{dy}{dx} \right)^{2} + \frac{1}{3!}\left( \frac{dy}{dx} \right)^{3} + \ldots$

Question

Dr. Abubacker · Accepted Answer

(c)
$x = 1 + \frac{dy}{dx} + \frac{1}{2!}\left( \frac{dy}{dx} \right)^{2} + \frac{1}{3!}\left( \frac{dy}{dx} \right)^{3} + \ldots.$
$\Rightarrow$ $x = e^{\frac{dy}{dx}} \Rightarrow \frac{dy}{dx} = \log_{e}x$
$\Rightarrow$ Degree of differential equation is 1.

Q. The degree of the differential equations $x = 1 + \left( \frac{dy}{dx} \right) + \frac{1}{2!}\left( \frac{dy}{dx} \right)^{2} + \frac{1}{3!}\left( \frac{dy}{dx} \right)^{3} + \ldots$

Explanation

Reviewed by Dr. Abubacker

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