Q. The order and degree of the differential equation $\sqrt{\sin x}\ (dx + dy) = \sqrt{\cos x}\ (dx - dy)$ are
A) (1,2)
B) (2,2)
C) (1,1)
D) (2,1)
Explanation
(c)
Given, $\sqrt{\sin x}\left( 1 + \frac{dy}{dx} \right) = \sqrt{\cos x}\left( 1 - \frac{dy}{dx} \right)$
$\Rightarrow$ $\frac{dy}{dx} = \frac{\sqrt{\cos x} - \sqrt{\sin x}}{\sqrt{\sin x} + \sqrt{\cos x}}$
$\therefore$ Order=1, degree=1
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.