Q. The differential equation of all straight lines passing through origin is
A) $y = \sqrt{x}\frac{dy}{dx}$
B) $\frac{dy}{dx} = y + x$
C) $\frac{dy}{dx} = y - x$
D) None of these
Explanation
(d)
The equation of all the straight lines passing through origin (0, 0) is
$y = mx$ ….(i)
Hence, required differential equation of all such lines is
$y = \left( \ \frac{dy}{dx}\ \right)x\ \ \ \left( \ \because m = \frac{dy}{dx}\ \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.